Integrand size = 26, antiderivative size = 26 \[ \int \frac {1}{x^2 \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)^{5/2}} \, dx=-\frac {2}{3 a c x^2 \sqrt {c+a^2 c x^2} \arctan (a x)^{3/2}}+\frac {8}{3 a^2 c x^3 \sqrt {c+a^2 c x^2} \sqrt {\arctan (a x)}}+\frac {4}{c x \sqrt {c+a^2 c x^2} \sqrt {\arctan (a x)}}+\frac {8 a \sqrt {2 \pi } \sqrt {1+a^2 x^2} \operatorname {FresnelC}\left (\sqrt {\frac {2}{\pi }} \sqrt {\arctan (a x)}\right )}{c \sqrt {c+a^2 c x^2}}+\frac {8 \text {Int}\left (\frac {1}{x^4 \left (c+a^2 c x^2\right )^{3/2} \sqrt {\arctan (a x)}},x\right )}{a^2}+\frac {44}{3} \text {Int}\left (\frac {1}{x^2 \left (c+a^2 c x^2\right )^{3/2} \sqrt {\arctan (a x)}},x\right ) \]
-2/3/a/c/x^2/arctan(a*x)^(3/2)/(a^2*c*x^2+c)^(1/2)+8*a*FresnelC(2^(1/2)/Pi ^(1/2)*arctan(a*x)^(1/2))*2^(1/2)*Pi^(1/2)*(a^2*x^2+1)^(1/2)/c/(a^2*c*x^2+ c)^(1/2)+8/3/a^2/c/x^3/(a^2*c*x^2+c)^(1/2)/arctan(a*x)^(1/2)+4/c/x/(a^2*c* x^2+c)^(1/2)/arctan(a*x)^(1/2)+8*Unintegrable(1/x^4/(a^2*c*x^2+c)^(3/2)/ar ctan(a*x)^(1/2),x)/a^2+44/3*Unintegrable(1/x^2/(a^2*c*x^2+c)^(3/2)/arctan( a*x)^(1/2),x)
Not integrable
Time = 9.86 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.08 \[ \int \frac {1}{x^2 \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)^{5/2}} \, dx=\int \frac {1}{x^2 \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)^{5/2}} \, dx \]
Not integrable
Time = 2.97 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {5503, 5503, 5440, 5439, 3042, 3785, 3833, 5560}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {1}{x^2 \arctan (a x)^{5/2} \left (a^2 c x^2+c\right )^{3/2}} \, dx\) |
\(\Big \downarrow \) 5503 |
\(\displaystyle -2 a \int \frac {1}{x \left (a^2 c x^2+c\right )^{3/2} \arctan (a x)^{3/2}}dx-\frac {4 \int \frac {1}{x^3 \left (a^2 c x^2+c\right )^{3/2} \arctan (a x)^{3/2}}dx}{3 a}-\frac {2}{3 a c x^2 \arctan (a x)^{3/2} \sqrt {a^2 c x^2+c}}\) |
\(\Big \downarrow \) 5503 |
\(\displaystyle -2 a \left (-4 a \int \frac {1}{\left (a^2 c x^2+c\right )^{3/2} \sqrt {\arctan (a x)}}dx-\frac {2 \int \frac {1}{x^2 \left (a^2 c x^2+c\right )^{3/2} \sqrt {\arctan (a x)}}dx}{a}-\frac {2}{a c x \sqrt {\arctan (a x)} \sqrt {a^2 c x^2+c}}\right )-\frac {4 \left (-8 a \int \frac {1}{x^2 \left (a^2 c x^2+c\right )^{3/2} \sqrt {\arctan (a x)}}dx-\frac {6 \int \frac {1}{x^4 \left (a^2 c x^2+c\right )^{3/2} \sqrt {\arctan (a x)}}dx}{a}-\frac {2}{a c x^3 \sqrt {\arctan (a x)} \sqrt {a^2 c x^2+c}}\right )}{3 a}-\frac {2}{3 a c x^2 \arctan (a x)^{3/2} \sqrt {a^2 c x^2+c}}\) |
\(\Big \downarrow \) 5440 |
\(\displaystyle -2 a \left (-\frac {4 a \sqrt {a^2 x^2+1} \int \frac {1}{\left (a^2 x^2+1\right )^{3/2} \sqrt {\arctan (a x)}}dx}{c \sqrt {a^2 c x^2+c}}-\frac {2 \int \frac {1}{x^2 \left (a^2 c x^2+c\right )^{3/2} \sqrt {\arctan (a x)}}dx}{a}-\frac {2}{a c x \sqrt {\arctan (a x)} \sqrt {a^2 c x^2+c}}\right )-\frac {4 \left (-8 a \int \frac {1}{x^2 \left (a^2 c x^2+c\right )^{3/2} \sqrt {\arctan (a x)}}dx-\frac {6 \int \frac {1}{x^4 \left (a^2 c x^2+c\right )^{3/2} \sqrt {\arctan (a x)}}dx}{a}-\frac {2}{a c x^3 \sqrt {\arctan (a x)} \sqrt {a^2 c x^2+c}}\right )}{3 a}-\frac {2}{3 a c x^2 \arctan (a x)^{3/2} \sqrt {a^2 c x^2+c}}\) |
\(\Big \downarrow \) 5439 |
\(\displaystyle -2 a \left (-\frac {4 \sqrt {a^2 x^2+1} \int \frac {1}{\sqrt {a^2 x^2+1} \sqrt {\arctan (a x)}}d\arctan (a x)}{c \sqrt {a^2 c x^2+c}}-\frac {2 \int \frac {1}{x^2 \left (a^2 c x^2+c\right )^{3/2} \sqrt {\arctan (a x)}}dx}{a}-\frac {2}{a c x \sqrt {\arctan (a x)} \sqrt {a^2 c x^2+c}}\right )-\frac {4 \left (-8 a \int \frac {1}{x^2 \left (a^2 c x^2+c\right )^{3/2} \sqrt {\arctan (a x)}}dx-\frac {6 \int \frac {1}{x^4 \left (a^2 c x^2+c\right )^{3/2} \sqrt {\arctan (a x)}}dx}{a}-\frac {2}{a c x^3 \sqrt {\arctan (a x)} \sqrt {a^2 c x^2+c}}\right )}{3 a}-\frac {2}{3 a c x^2 \arctan (a x)^{3/2} \sqrt {a^2 c x^2+c}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle -2 a \left (-\frac {2 \int \frac {1}{x^2 \left (a^2 c x^2+c\right )^{3/2} \sqrt {\arctan (a x)}}dx}{a}-\frac {4 \sqrt {a^2 x^2+1} \int \frac {\sin \left (\arctan (a x)+\frac {\pi }{2}\right )}{\sqrt {\arctan (a x)}}d\arctan (a x)}{c \sqrt {a^2 c x^2+c}}-\frac {2}{a c x \sqrt {\arctan (a x)} \sqrt {a^2 c x^2+c}}\right )-\frac {4 \left (-8 a \int \frac {1}{x^2 \left (a^2 c x^2+c\right )^{3/2} \sqrt {\arctan (a x)}}dx-\frac {6 \int \frac {1}{x^4 \left (a^2 c x^2+c\right )^{3/2} \sqrt {\arctan (a x)}}dx}{a}-\frac {2}{a c x^3 \sqrt {\arctan (a x)} \sqrt {a^2 c x^2+c}}\right )}{3 a}-\frac {2}{3 a c x^2 \arctan (a x)^{3/2} \sqrt {a^2 c x^2+c}}\) |
\(\Big \downarrow \) 3785 |
\(\displaystyle -2 a \left (-\frac {8 \sqrt {a^2 x^2+1} \int \frac {1}{\sqrt {a^2 x^2+1}}d\sqrt {\arctan (a x)}}{c \sqrt {a^2 c x^2+c}}-\frac {2 \int \frac {1}{x^2 \left (a^2 c x^2+c\right )^{3/2} \sqrt {\arctan (a x)}}dx}{a}-\frac {2}{a c x \sqrt {\arctan (a x)} \sqrt {a^2 c x^2+c}}\right )-\frac {4 \left (-8 a \int \frac {1}{x^2 \left (a^2 c x^2+c\right )^{3/2} \sqrt {\arctan (a x)}}dx-\frac {6 \int \frac {1}{x^4 \left (a^2 c x^2+c\right )^{3/2} \sqrt {\arctan (a x)}}dx}{a}-\frac {2}{a c x^3 \sqrt {\arctan (a x)} \sqrt {a^2 c x^2+c}}\right )}{3 a}-\frac {2}{3 a c x^2 \arctan (a x)^{3/2} \sqrt {a^2 c x^2+c}}\) |
\(\Big \downarrow \) 3833 |
\(\displaystyle -2 a \left (-\frac {2 \int \frac {1}{x^2 \left (a^2 c x^2+c\right )^{3/2} \sqrt {\arctan (a x)}}dx}{a}-\frac {4 \sqrt {2 \pi } \sqrt {a^2 x^2+1} \operatorname {FresnelC}\left (\sqrt {\frac {2}{\pi }} \sqrt {\arctan (a x)}\right )}{c \sqrt {a^2 c x^2+c}}-\frac {2}{a c x \sqrt {\arctan (a x)} \sqrt {a^2 c x^2+c}}\right )-\frac {4 \left (-8 a \int \frac {1}{x^2 \left (a^2 c x^2+c\right )^{3/2} \sqrt {\arctan (a x)}}dx-\frac {6 \int \frac {1}{x^4 \left (a^2 c x^2+c\right )^{3/2} \sqrt {\arctan (a x)}}dx}{a}-\frac {2}{a c x^3 \sqrt {\arctan (a x)} \sqrt {a^2 c x^2+c}}\right )}{3 a}-\frac {2}{3 a c x^2 \arctan (a x)^{3/2} \sqrt {a^2 c x^2+c}}\) |
\(\Big \downarrow \) 5560 |
\(\displaystyle -2 a \left (-\frac {2 \int \frac {1}{x^2 \left (a^2 c x^2+c\right )^{3/2} \sqrt {\arctan (a x)}}dx}{a}-\frac {4 \sqrt {2 \pi } \sqrt {a^2 x^2+1} \operatorname {FresnelC}\left (\sqrt {\frac {2}{\pi }} \sqrt {\arctan (a x)}\right )}{c \sqrt {a^2 c x^2+c}}-\frac {2}{a c x \sqrt {\arctan (a x)} \sqrt {a^2 c x^2+c}}\right )-\frac {4 \left (-8 a \int \frac {1}{x^2 \left (a^2 c x^2+c\right )^{3/2} \sqrt {\arctan (a x)}}dx-\frac {6 \int \frac {1}{x^4 \left (a^2 c x^2+c\right )^{3/2} \sqrt {\arctan (a x)}}dx}{a}-\frac {2}{a c x^3 \sqrt {\arctan (a x)} \sqrt {a^2 c x^2+c}}\right )}{3 a}-\frac {2}{3 a c x^2 \arctan (a x)^{3/2} \sqrt {a^2 c x^2+c}}\) |
3.11.99.3.1 Defintions of rubi rules used
Int[sin[Pi/2 + (e_.) + (f_.)*(x_)]/Sqrt[(c_.) + (d_.)*(x_)], x_Symbol] :> S imp[2/d Subst[Int[Cos[f*(x^2/d)], x], x, Sqrt[c + d*x]], x] /; FreeQ[{c, d, e, f}, x] && ComplexFreeQ[f] && EqQ[d*e - c*f, 0]
Int[Cos[(d_.)*((e_.) + (f_.)*(x_))^2], x_Symbol] :> Simp[(Sqrt[Pi/2]/(f*Rt[ d, 2]))*FresnelC[Sqrt[2/Pi]*Rt[d, 2]*(e + f*x)], x] /; FreeQ[{d, e, f}, x]
Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_.)*((d_) + (e_.)*(x_)^2)^(q_), x_ Symbol] :> Simp[d^q/c Subst[Int[(a + b*x)^p/Cos[x]^(2*(q + 1)), x], x, Ar cTan[c*x]], x] /; FreeQ[{a, b, c, d, e, p}, x] && EqQ[e, c^2*d] && ILtQ[2*( q + 1), 0] && (IntegerQ[q] || GtQ[d, 0])
Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_.)*((d_) + (e_.)*(x_)^2)^(q_), x_ Symbol] :> Simp[d^(q + 1/2)*(Sqrt[1 + c^2*x^2]/Sqrt[d + e*x^2]) Int[(1 + c^2*x^2)^q*(a + b*ArcTan[c*x])^p, x], x] /; FreeQ[{a, b, c, d, e, p}, x] && EqQ[e, c^2*d] && ILtQ[2*(q + 1), 0] && !(IntegerQ[q] || GtQ[d, 0])
Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_.)*(x_)^(m_.)*((d_) + (e_.)*(x_)^ 2)^(q_), x_Symbol] :> Simp[x^m*(d + e*x^2)^(q + 1)*((a + b*ArcTan[c*x])^(p + 1)/(b*c*d*(p + 1))), x] + (-Simp[c*((m + 2*q + 2)/(b*(p + 1))) Int[x^(m + 1)*(d + e*x^2)^q*(a + b*ArcTan[c*x])^(p + 1), x], x] - Simp[m/(b*c*(p + 1)) Int[x^(m - 1)*(d + e*x^2)^q*(a + b*ArcTan[c*x])^(p + 1), x], x]) /; F reeQ[{a, b, c, d, e, m}, x] && EqQ[e, c^2*d] && IntegerQ[m] && LtQ[q, -1] & & LtQ[p, -1] && NeQ[m + 2*q + 2, 0]
Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_.)*(u_.), x_Symbol] :> Unintegrab le[u*(a + b*ArcTan[c*x])^p, x] /; FreeQ[{a, b, c, p}, x] && (EqQ[u, 1] || M atchQ[u, ((d_.) + (e_.)*x)^(q_.) /; FreeQ[{d, e, q}, x]] || MatchQ[u, ((f_. )*x)^(m_.)*((d_.) + (e_.)*x)^(q_.) /; FreeQ[{d, e, f, m, q}, x]] || MatchQ[ u, ((d_.) + (e_.)*x^2)^(q_.) /; FreeQ[{d, e, q}, x]] || MatchQ[u, ((f_.)*x) ^(m_.)*((d_.) + (e_.)*x^2)^(q_.) /; FreeQ[{d, e, f, m, q}, x]])
Not integrable
Time = 0.18 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.85
\[\int \frac {1}{x^{2} \left (a^{2} c \,x^{2}+c \right )^{\frac {3}{2}} \arctan \left (a x \right )^{\frac {5}{2}}}d x\]
Exception generated. \[ \int \frac {1}{x^2 \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)^{5/2}} \, dx=\text {Exception raised: TypeError} \]
Exception raised: TypeError >> Error detected within library code: inte grate: implementation incomplete (constant residues)
Timed out. \[ \int \frac {1}{x^2 \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)^{5/2}} \, dx=\text {Timed out} \]
Exception generated. \[ \int \frac {1}{x^2 \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)^{5/2}} \, dx=\text {Exception raised: RuntimeError} \]
Not integrable
Time = 214.48 (sec) , antiderivative size = 3, normalized size of antiderivative = 0.12 \[ \int \frac {1}{x^2 \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)^{5/2}} \, dx=\int { \frac {1}{{\left (a^{2} c x^{2} + c\right )}^{\frac {3}{2}} x^{2} \arctan \left (a x\right )^{\frac {5}{2}}} \,d x } \]
Not integrable
Time = 0.37 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.92 \[ \int \frac {1}{x^2 \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)^{5/2}} \, dx=\int \frac {1}{x^2\,{\mathrm {atan}\left (a\,x\right )}^{5/2}\,{\left (c\,a^2\,x^2+c\right )}^{3/2}} \,d x \]